Download the app

Questions  

 Let f(x) satisfy all the conditions of Lagrange's mean value theorem in [0,2] . If f(0)=0 and f(x)12 for all x in [0,2], then 

 

a
fx<12
b
fx≤1
c
fx=2x
d
f(x)=3 for at least one x in [0,2]

detailed solution

Correct option is B

By using lagrange's mean value theorem ,f(b)−f(a)b−a=f′(x)⇒f(2)−f(0)2−0=f′(x)⇒f(2)−02=f′(x)integrating on both sides⇒f(x)=f(2)2x+c (∵f(0)=0⇒c=0)∴f(x)=f(2)2x ……(1) Also, f′(x)≤12⇒f(2)2≤12From  Eq. (1), |f(x)|=f(2)2x=f(2)2|x|≤12|x| In interval [0,2], for maximum value of x take x=2|f(2)|≤12⋅2⇒|f(2)|≤1hence fx≤1

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

Consider the function f(x)=8x27x+5 on the interval [6,6]. the value of c satisfying the conclusion of Lagrange’s mean value theorem is ______________.


phone icon
whats app icon