Let f(x)=sec−1([1+sin2x]); where [.] denotes greatest integer function. Then the set of points where f(x) is not continuous is
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a
{nπ2,n∈I}
b
{(2n−1)π2,n∈I}
c
{(n−1)π2,n∈I}
d
{nπ/n∈I}
answer is B.
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Detailed Solution
f(nπ+)=sec−11=0 and f(nπ−)=sec−11=0 and f(nπ)=0 ∴f is continuous at x=nπ f((2n−1)π2+)=sec−11=0 but f((2n−1)π2)=sec−12=π3 ∴f is discontinuous at x=(2n−1)π2 for all n∈I