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Q.

Let f(x)=sec−1([1+sin2x]);  where [.] denotes greatest integer function. Then the set of points where f(x) is not continuous is

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a

{nπ2,n∈I}

b

{(2n−1)π2,n∈I}

c

{(n−1)π2,n∈I}

d

{nπ/n∈I}

answer is B.

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Detailed Solution

f(nπ+)=sec−11=0  and f(nπ−)=sec−11=0  and f(nπ)=0 ∴f  is continuous at x=nπ f((2n−1)π2+)=sec−11=0  but f((2n−1)π2)=sec−12=π3 ∴f  is discontinuous at x=(2n−1)π2  for all n∈I
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