Let f(x)=2π(sin−1[x]+cot−1[x]+tan−1[x])where [x]denotes greatest integer function less than equal to x. If A and B denotes the domain and Range of f(x)respectively, then the number of integers in A∪B is
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answer is 4.
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Detailed Solution
Given fx=2πsin-1x+cot-1x+tan-1x sin-1 domain is -1,1, cot-1 and tan-1 domain is -∞,∞. ∴The domain of fx is [-1,2). ∵if x∈ [-1,2), then x can take -1,0,1 only ∴A=[-1,2) Now if x∈[-1,0), then x=-1 ⇒ fx=2π-π2+3π4-π4=0 for x∈[0,1), then x=0 ⇒ fx=2π0+π2+0=1 for x∈[1,2), then x=1 ⇒fx=2ππ2+π4+π4=2 ∴range of fx=B={0,1,2} ∴A∪B=[-1,2)∪{0,1,2}=-1,2 ∴The number of integers in A∪B is 4