Let f(x)=sinx and g(x)=loge|x| . If the ranges of the composition functions fog and gof are R1 and R2 , respectively, then
R1={u:−1≤u<1},R2={v:−∞<v<0}
R1={u:−∞<u<0},R2={v:−∞<v<0}
R1={u:−1<u<1},R2={v:−∞<v<0}
R1={u:−1≤u≤1},R2={v:−∞<v≤0}
fx = sinx and gx=logx
⇒ fogx =fgx=flogx =sinlogx ∈-1,1 since logx, range is R
R1=u/ -1≤u≤1
also , gofx =gfx=gsinx=logsinx
since 0≤sinx≤1 ⇒-∞<logsinx≤0
R2=v/-∞<v≤0