First slide
Evaluation of definite integrals
Question

Let f(x)=sinx+r=02cosx+2 rπ3 

g(x)=cosx+r=02sinx+2 rπ3 

h(x)=max{f(x),g(x)}

NA
Question

ππg{f(x)} sin 2x dx  is equalent to

Solution

f(x)=sinx+r=02cosx+23=sinx+cosx+cosx+2π3+cosx+4π3

=sinx+cosx212cosx=sinx

similarly g(x) = cosx

ππg {f(x)} sin2x dx=ππcos(sinx)sin2x dx=0 

since integrand is odd

Question

π/4π[ h(x) ] {f(x)}2dx where [.] denotes greatest integer function is

Solution

π/4π[h(x)]{f(x)}2dx=x/4π[sinx]sin2xdx=0

Question

0π{g(x)}337dx=

Solution

0π{g(x)}337dx=0πcos337xdx=0πcos337(πx)dx=0πcos337xdx 0πcos337xdx=0

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