Q.
Let f(x)=sinx+∑r=02 cosx+2 rπ3 g(x)=cosx+∑r=02 sinx+2 rπ3 h(x)=max{f(x),g(x)}∫−ππ g{f(x)} sin 2x dx is equalent to∫π/4π [ h(x) ] {f(x)}2dx where [.] denotes greatest integer function is∫0π {g(x)}337dx=
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a
2∫0π g {f(x)} sin 2x dx
b
4∫0π/2 g {f(x)} sin 2x dx
c
∫−π/2π/2 cos2x⋅sin5xdx
d
1
e
π
f
3π4
g
0
h
5π4
i
0
j
π
k
337π2
l
1
answer is