Let f(x)=x4ax−x2,(a>0).Then f(x) is
increasing in (0, 3a)
decreasing in 5a,∞
increasing in (0,4a)
decreasing in (3a, 4a)
f(x)=x4ax−x2 (domain is [0,4a]) ∴ f′(x)=4ax−x2+x(4a−2x)24ax−x2 =2x(3a−x)4ax−x2 Now, if f′(x)>0,then 2x(3a−x)>0 or 2x(x−3a)<0 or x∈(0,3a) Thus,/(x) increases in (0, 3a) and decreases in (3a,4a).