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Questions  

 Let f(x)=ax+b and g(x)=cx+d,a0,c0. Assume a=1,b=2. If (fg)(x)=(gof)(x) for all x, what can you 

 say about c and d?

a
c and d both arbitary
b
c = 1, d arbitrary
c
c arbitrary, d
d
c=1,d=1

detailed solution

Correct option is B

(fog)(x)=f(g(x))=a(cx+d)+b and (gof)(x)=f(f(x))=c(ax+b)+d Given that (fog)(x)=(gof)(x) and at a=1,b=2⇒cx+d+2=cx+2c+d⇒c=1 and d is arbitary

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Similar Questions

Which of the following statements are incorrect?

 I. If f(x) and g(x) are one-one then f(x)+g(x) is also one-one

 II. If f(x) and g(x) are one-one then f(x)g(x) is also one-one

 III. If f(x) is odd then it is necessarily one-one. 


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