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$Let f (x) = |x - 2| and \underset{(n times)}{\underset{⏟}{g (x) = f (f (f \dots \dots (f (x))) \dots)}} . If equation g (x) = k, k \in (0, 2) has 8$ $distinct solutions than value of n is equal to$

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Correct option is B

If n=1 then fx =x-2 , number of solutions =2 ; If n=2 then ffx=x-2-2 , number of solutions =4 ;If n=3 then fffx=x-2-2-2, number of solutions =6; If n=4 then ffff = x-2-2-2-2 ,number of solutions =8;

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Let fx=x-2 and g(x)=f(f(f……(f(x)))…)⏟(n times ). If equation gx=k, k∈0,2 has 8 distinct solutions than value of n is equal to

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$Let f (x) = |x - 2| and \underset{(n times)}{\underset{⏟}{g (x) = f (f (f \dots \dots (f (x))) \dots)}} . If equation g (x) = k, k \in (0, 2) has 8$ $distinct solutions than value of n is equal to$