Let fx=x-2 and g(x)=f(f(f……(f(x)))…)⏟(n times ). If equation gx=k, k∈0,2 has 8 distinct solutions than value of n is equal to
3
4
5
8
If n=1 then fx =x-2 , number of solutions =2 ;
If n=2 then ffx=x-2-2 , number of solutions =4 ;
If n=3 then fffx=x-2-2-2, number of solutions =6;
If n=4 then ffff = x-2-2-2-2 ,number of solutions =8;