Let f(x)=1 x-1and g(x)=1x2+x-2. Then the set of points where (gof) (x) is discontinuous, is
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a
{1}
b
{-1,2}
c
{12,1,2}
d
{12,1}
answer is C.
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Detailed Solution
f(x)=1x−1 is discontinuous at x=1 . (gof) (x)=g(f(x))=−(x−1)2(2x−1)(x−2), which is not defined at x=12,2. Hence the set of points where (gof) ( x ) is discontinuous is {12,1,2}