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Q.

Let f'x=192x32+sin4πx for all x∈ℝwith  f12=0.If m≤∫1/21fxdx≤M, then the possible values of  m and M are

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a

m=13,M=24

b

m=14,M=12

c

m=−11, M=0

d

m=1, M=12

answer is D.

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Detailed Solution

2≤2+sin4πx≤313≤12+sin4π≤121923x3≤f'x≤1922x3⇒64∫12tx3dx≤ft−f12≤96∫12tx3dx⇒16t4−116≤ft≤24t4−116⇒∫12116t4−1dt≤∫121ftdt≤∫12124t4−32dt⇒165t5-t121≤∫121ftdt≤ 24t55−3t2121⇒1651−132−12≤∫121ftdt≤2451−132−32.12⇒3110−12≤∫121ftdt≤9320−34⇒2.6≤∫121ftdt≤3.9⇒m=1,M=12
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