Download the app

Questions  

Let f(x)=0x6u2du. Then the real roots of the equation

x2f(x)=0 are

Remember concepts with our Masterclasses.

80k Users
60 mins Expert Faculty Ask Questions
a
x=±6
b
x=±3
c
x=±2
d
x=±1

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is C

Since f′(x)=6−x2, the equation x2−f′(x)=0 becomes         x2−6−x2=0⇒x4+x2−6=0⇒ x2−2x2+3=0⇒x2−2=0x2+3≠0⇒ x=±2.


Similar Questions

The value of  limx0xexdx20xe2x2dx is


whats app icon
phone icon