Letfx=a2-5a+4x3-6a2-5a+1x-tanx(sgnx) be an even function for all x∈R. Then the sum of all possible values of a is (where [.] and {.} denote greatest integer function and fractional part function, respectively)
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
176
b
536
c
313
d
353
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
fx=αx3-βx-tanxsgnx f-x=fx or -αx3+βx-tanx sgnx =αx3-βx-tanx(sgnx) or 2-αx2-βx=0∀x∈R or α=0 and β=0 ∴ a2-5a+4=0 and 6a2-5a+1=0 or x=1,4 and x=12,13 ∴ a=1+13,1+12,4+13,4+12 Sum of values of a=353