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Differentiability
Question

 Let f(x)=1|x|, |x|1ax2+b,|x|<1 be continuous and differentiable every where then 

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Solution

   f(x)=1|x|, |x|1ax2+b,|x|<1 f is continuous at x=1 a+b=1 f1(x)=-1x2, |x|12ax,    |x|<1 2a=-1a=-12, b=32

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