Let f(x+y)=f(x)f(y) and f(x)=1+(sin2x)g(x) where g(x) is continuous. Then g′(x) is equal to
f(x) g(0)
2g(0)
2f(x) g(0)
None of these
f(x)=limh→0fx+h−fxhlimh→0fxfh−fxh = fxlimh→0fh−1h =fxlimh→01+sin2hgh−1h =2fxlimh→0sin2h2hlimh→0gh = 2fx g0Hence (3)is the correct answer.