Let f(x+y)=f(x)f(y) for all x and y and f(1)=2 . If in a triangle ABC,a=f(3) , b = f(1) + f(3), c = f(2) + f(3) then 2A is equal to
C
2C
3C
4C
f(x+y)=f(x)f(y)⇒f(x)=axf(1)=2⇒a=2⇒f(x)=2x⇒a=8, b=10, c=12cosA=34Cos2A=1/8,cosC=1/8∴2A=C