Let f(x+y)=f(x)f(y) and f(x)=1+(sin2x)g(x) where g(x) is continues. Then f1(x) equals
f(x)g(0)
2f(x)g(0)
2g(0)
2f(0)
f'(x)=limh→0 f(x+h)−f(x)h=limh→0 f(x)f(h)−f(x)h=f(x)limh→0 f(h)−1h=f(x)limh→0 1+(sin2h)g(h)−1h=f(x)limh→0 sin2hhlimh→0 (h)=2f(x)g(0)