Let f:{x,y,z}→{1,2,3} be a one-one function. If it is given that exactly one of the following statements is true, Statement-1: f(x)=1, Statement-2: f(y)≠1, Statement-3: f(z)≠2. then f−1(1) is
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a
x
b
y
c
z
d
none of these
answer is B.
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Detailed Solution
If we take f(x)= 1, then f(y)≠1 as the function is one-one. So f(x)≠1If f(z)=1, then statements 2 and 3 both are true, so f(z)≠1 hence f(y)=1 and f-1(1)=y.