Let f:{x,y,z}→{1,2,3} be a one-one mapping such that only one of the following three statements is true and
remaining two are false: f(x)≠2,f(y)=2,f(z)≠1, then
f(x)>f(y)>f(z)
f(x)<f(y)<f(z)
f(y)<f(x)<f(z)
f(y)<f(z)<f(x)
case 1 : Let fx ≠2 be true and fy=2,fz≠1 are false
then fx≠2,fy≠2,fz=1 ⇒ fx=3 ,fy=3 ,fz=1 , which is not one-one
case 2 : let fy =2 be true and fx≠2,fz≠1 be false then fy=2 , fx =2 ,fz=1 , which is not one-one
case 3 : let fz≠1 be true and fx≠2 ,fy=2 are false then fx =2 ,fy ≠2, fz ≠1 are true f(x)=2,f(y)=1,f(z)=3, one to one