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Questions  

 Let f:{x,y,z}{1,2,3} be a one-one mapping such  that only one of the following three statements is true and 

 remaining two are false: f(x)2,f(y)=2,f(z)1, then 

a
f(x)>f(y)>f(z)
b
f(x)
c
f(y)
d
f(y)

detailed solution

Correct option is C

case 1 :  Let fx ≠2 be true and fy=2,fz≠1 are false then fx≠2,fy≠2,fz=1 ⇒ fx=3 ,fy=3 ,fz=1 , which is not one-one   case 2 :  let fy =2 be true and fx≠2,fz≠1 be false   then    fy=2 , fx =2 ,fz=1 , which is not one-one    case 3 : let fz≠1 be true and fx≠2 ,fy=2 are false     then   fx =2 ,fy ≠2, fz ≠1 are true      f(x)=2,f(y)=1,f(z)=3, one to one

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Similar Questions

Which of the following statements are incorrect?

 I. If f(x) and g(x) are one-one then f(x)+g(x) is also one-one

 II. If f(x) and g(x) are one-one then f(x)g(x) is also one-one

 III. If f(x) is odd then it is necessarily one-one. 


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