Let the function f:R→R be defined by f(x)=2x+sinx for x∈R . Then f is
one-to-one and onto
one-to-one but not onto
onto but not one-to-one
neither one-to-one nor onto
Given that f(x)=2x+sinx,x∈R
or f′(x)=2+cosx But −1≤cosx≤1 or 1≤2+cosx≤3∴ f′(x)>0∀x∈R
Therefore, f(x) is strictly increasing and, hence, one-one. Also, as x→∞,f(x)→∞, and x→−∞,f(x)→−∞ . Therefore,
Range of f(x)=R=co-domain of f(x)
Hence, f(x) is onto.
Thus, f(x) is one-one and onto.