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Let the function
$f (x) = 3 x^{2} - 4 x + 8 \log (1 + |x|)$ be defined on the interval [0, 1]. The even extension of f(x) of the interval [-1, 1] is

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3x2−4x+8log1+x

3x2+4x−8log1+x

3x2−4x−8log1+x

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Correct option is A

f(x)=−f(x) x∈[0,1] −f(−x) x∈[−1,0]f(x)=3x2−4x+8log1+xx∈[0,1]f(x)=3x2+4x+8log1+xx∈[−1,0]∴f(x)=3x2−4x+8log1+xx∈[−1,1]

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Let the functionf(x)=3x2−4x+8log1+x be defined on the interval [0, 1]. The even extension of f(x) of the interval [-1, 1] is

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Let the function
$f (x) = 3 x^{2} - 4 x + 8 \log (1 + |x|)$ be defined on the interval [0, 1]. The even extension of f(x) of the interval [-1, 1] is