Let the functions :(−1,1)→ℝ and g:(−1,1)→(−1,1) be defined by f(x)=|2x−1|+|2x+1| and g(x)=x−[x] where [x] denotes the greatest integer less than or equal to x. Let f∘g:(−1,1)→ℝ be the composite function defined by (f∘g)(x)=f(g(x)) . Suppose c is the number of points in the interval (−1,1) at which f∘g is NOT continuous, and suppose d is the number of points in the interval (−1,1) at which f∘g is NOT differentiable. Then the value of c+d is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
answer is 4.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
f(x)=|2x−1|+|2x+1|g(x)={x}f(g(x))=|2{x}−1|+|2{x}+1| =2{x}≤1/24{x}{x}>1/2 discontinuous at x=0⇒c=1 Non differential at x=−1/2, 0, 1/2⇒d=3∴ c+d=4