Let $$f(x)$$ $$=$$ (x$$ $$+$$ $$1)2$$ – $$1$$, x ≥ –$$1$$ then the set $${x$$ : $$f(x) $$=$$ f –$$1(x)}$$ is equal to

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Let y $$=$$ (x$$ $$+$$ $$1)2$$ – $$1$$, x ≥ – $$1$$⇒$$(x$$ $$+$$ $$1)2$$ $$=$$ y $$+$$ $$1$$⇒x $$+$$ $$1$$ $$=$$ y $$+$$ $$1$$ as x ≥ – $$1$$⇒x $$=$$ – $$1$$ $$+y+1$$  , y ≥ – $$1Thus$$              $$f-1(x) $$=$$ – $$1$$ $$+x+1$$ So            f (x) $$=$$ f –$$1(x)$$⇒$$(x$$ $$+$$ $$1)2$$  – $$1$$ $$=$$ – $$1$$ $$+$$ $$x+1$$⇒x $$+$$ $$1$$ $$=$$ $$0$$ or $$(x$$ $$+$$ $$1)3/2$$ $$=$$ $$1$$⇒x $$=$$ – $$1$$ or x $$=$$  $$0$$

Let f(x) = (x + 1)² – 1, x ≥ –1 then the set {x : f(x) = f ^–1(x)} is equal to

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Let f(x) = (x + 1)2 – 1, x ≥ –1 then the set {x : f(x) = f –1(x)} is equal to

Remember concepts with our Masterclasses.

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Let f(x) = (x + 1)² – 1, x ≥ –1 then the set {x : f(x) = f ^–1(x)} is equal to