Let f(x)=sin x +cos x+ tan x+ arc sin x+ arc cos x + arc tan x . If M and m are maximum and minimum values of f(x) , then their arithmetic mean is equal to
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a
π2+cos1
b
π2+sin1
c
π4+tan1+cot1
d
None of these
answer is A.
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Detailed Solution
Domain of f is [-1,1]fx=sinx+cosx+tanx+sin-1x+cos-1x+tan-1xfx=sinx+cosx+tanx+π2+tan-1xf'x=cosx-sinx+sec2x+0+11+x2 here,sec2≥1 and 11+x2∈12,1 and cosx-sinx ∈-2,2hence f'x>0⇒ f is increasingRange is [f(-1),f(1)]∴fxmin=f-1=-sin1+cos1-tan1+π2-π4 m=π4+cos1-sin1-tan1∴fxmax=f1=sin1+cos1+tan1+π2+π4 M=3π4+cos1+sin1+tan1 ⇒M+m2=π2+cos1