Q.
Let gx=fx-1. If fx+f1-x=2∀x∈R, then gx is symmetrical about
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a
the origin
b
the line x=12
c
the point 1,0
d
the point 12,0
answer is D.
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Detailed Solution
fx-1+f1-x-1=0So, gx+g1-x=0.Replacing x by x+12, We get g12+x+g12-x=0.So, it is symetrical about 12,0.
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