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Questions  

 Let G(x)=1ax1+12F(x), where a is a positive real  number not equal to 1 and F(x) is an odd function. Which  of the following statements is true? 

a
G(x) is an odd function
b
G(x) is an even function
c
G(x) is neither even function nor odd function
d
Whether G(x) is an odd function or an even function,  it depends on the value of a

detailed solution

Correct option is B

G(x)=1ax−1+12F(x)∴ G(−x)=1a−x−1+12F(−x) =−ax1−ax+12F(x) =axax−1−12F(x) =ax−1+1ax−1−12F(x) =1+1ax−1−12F(x)=1ax−1+12F(x)=G(x)∴G(x) is an even function.

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