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Let $g (x) = \{\begin{array}{cc} 1 & , 0 \leq x < 1 \\ x^{3} & , 1 \leq x < 4 \\ \sqrt{x} & , 4 \leq x < 9 \end{array} then \int_{0}^{9} g (x) d x$ is

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Correct option is C

∫09 g(x)dx=∫01 dx+∫14 x3dx+∫49 xdx=1+1444−1+2393/2−43/2=92912

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Let g(x)=1,0≤x<1x3,1≤x<4x,4≤x<9 then ∫09 g(x)dx is

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Let $g (x) = \{\begin{array}{cc} 1 & , 0 \leq x < 1 \\ x^{3} & , 1 \leq x < 4 \\ \sqrt{x} & , 4 \leq x < 9 \end{array} then \int_{0}^{9} g (x) d x$ is