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Q.

Let A(h, k), B(1, 1) and C(2, 1) be the vertices of a right angled triangle with AC as its hypotenuse. If the area of the triangle is 1, then the set of values which ‘k’ can take is given by

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a

{1, 3}

b

{0, 2}

c

{–1, 3}

d

(–3, –2)

answer is C.

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Detailed Solution

12×1(k−1)=±1 k−1=±2 k=3 k=−1

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