Let I=∫-∞∞dx1+x2
Statement-1:I =π
Statement-2: The integrand is even and limb→∞F(b)
=π,F(b)=∫0bdx1+x2
STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is a correct explanation for STATEMENT-1
STATEMENT-1 is True, STATEMENT-2 is True; STATEMENT-2 is NOT a correct explanation forSTATEMENT-1
STATEMENT-1 is True, STATEMENT-2 is False
STATEMENT-1 is False, STATEMENT-2 is True
The integrand is even, so
∫-∞∞dx1+x2=2∫0∞dx1+x2
∫0∞dx1+x2=limb→∞∫0bdx1+x2=limb→∞tan-1b-0=π2