Q.
Let a→=2i^+j^−k^ and b→=i^+2j^+k^ be two vectors. Consider a vector c→=αa→+βb→,α,β∈ℝ. If the projection of c→ on the vector a→+b→ is 32, , then the minimum value of c→−a→×b→.c→ equals
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answer is 18.
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Detailed Solution
a¯+b=3i+3j and c=2α+βi+α+2βj+β-αkGiven the projection of c¯ on a¯+b¯ is 32c¯·a¯+b¯a¯+b¯=329α+β=18α+β=2 Considerc¯-a¯×b¯ ·c= c¯2=6α2+6αβ+6β2 since a¯×b¯.c¯=0 as a¯,b¯,c¯ are coplanar =6α2+α2-α+2-α2 =6α2-2α+4 ≤63 since the minimum value of the quadratic expression is 3 =18
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