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Q.

Let A=aij3×3, where aij∈C the set of complex numbers. If det⁡(A)=2−3i,then det⁡A−1 equals:

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a

113(2−3i)

b

113(2+3i)

c

2−3i

d

2+3i

answer is B.

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Detailed Solution

det⁡A−1=1det⁡(A)=12−3i=2+3i22+32=113(2+3i)
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