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Let $A = {(a_{i j})}_{3 \times 3},$ where $a_{i j} \in C$ the set of complex numbers. If $\det (A) = 2 - 3 i,$ then $\det (A^{- 1})$ equals:

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113(2−3i)

113(2+3i)

2−3i

2+3i

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Correct option is B

det⁡A−1=1det⁡(A)=12−3i=2+3i22+32=113(2+3i)

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Let A=aij3×3, where aij∈C the set of complex numbers. If det⁡(A)=2−3i,then det⁡A−1 equals:

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Let $A = {(a_{i j})}_{3 \times 3},$ where $a_{i j} \in C$ the set of complex numbers. If $\det (A) = 2 - 3 i,$ then $\det (A^{- 1})$ equals: