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 Let In=0π/4tannxdx, then I2+I4,I3+I5,I4+I6,I5+I7, are in 

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detailed solution

Correct option is A

In+In-2=1n−1In+2+In=1n+1I2+I4=13I3+I5=14I4+I6=1513,14,15... are H.P


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