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Let In=0π/2xncos x dx then I8+56I6  is equal to

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a
π26
b
π28
c
π26-1
d
π28-1

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detailed solution

Correct option is B

In=∫0π/2 xncos⁡ xdx=xnsin⁡ x0π/2−n∫0π/2 xn−1sin⁡ xdx=π2n−n−xn−1cos⁡ x0π/2+(n−1)∫0π/2 xn−2cos⁡ xdx=π2n−n(n−1)In−2I8+8.7I6=π28


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