Let I1=∫π/6π/3 sinxxdx,I2=∫π/6π/3 sin(sinx)sinxdx and I3=∫π/6π/3 sin(tanx)tanxdx Then arrange I1,I2 and I3 in the decreasing order of their values.
I1>I2>I3
I2>I1>I3
I3>I2>I1
I1=I2=I3
f(x)=sinxx is a decreasing function and sinxx>0 for all x in (0,π) .
Since sinx<x<tanx sin(sinx)sinx>sinxx>sin(tanx)tanx for π6<x<π3
∴ I2>I1>I3