First slide
Evaluation of definite integrals
Question

Let I=0πx2cosxdx and J=0πxsinxdx

Statement-1: I=-2π

Statement-2: I=2 J

 

Moderate
Solution

Integrating by parts

0πx2cosx=x2sinx0π-0π2xsinxdx=-2J

J=0πxsinxdx=0ππsinxdx-0πxsinxdx

  2J=π(-cosx)0π=2πJ=π

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