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Let $I = \int_{1}^{2} \frac{10 x^{2}}{{(x^{3} + 1)}^{2}} d x and J = \int_{2}^{9} \frac{d x}{x^{2}}$
Statement-1: $I = \frac{35}{27}$
Statement-2: $3 I = 10 J$

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Correct option is A

Setx3+1=u⇒∫1210x2x3+12dx=103∫29duu2=103-1u29=3527.

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Let I=∫1210x2x3+12dx and J=∫29dxx2 Statement-1: I=3527Statement-2: 3 I=10 J

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Let $I = \int_{1}^{2} \frac{10 x^{2}}{{(x^{3} + 1)}^{2}} d x and J = \int_{2}^{9} \frac{d x}{x^{2}}$
Statement-1: $I = \frac{35}{27}$
Statement-2: $3 I = 10 J$