Let L be the line  passing through the point P1,2,0 and perpendicular to the plane r¯⋅3i¯+4k¯=0 if line  intersects the plane r¯⋅i¯−j¯+k¯=13 at point Q, then  Q is

The equation of the line passing through the point  P1,2,0and perpendicular to the plane r¯⋅3i¯+4k¯=0  is x−13=y−20=z−04=kThe general point on the above line is3k+1,2,4kThis point lies on the planex−y+z=13It implies that    3k+1−2+4k=137k=14k=2         Therefore, the pointQ7,2,8