Let L be the line passing through the point $$P1$$,$$2$$,$$0$$ and perpendicular to the plane r¯⋅$$3i$$¯$$+4k$$¯$$=0$$ if line intersects the plane r¯⋅i¯−j¯$$+k$$¯$$=13$$ at point Q, then Q is

Question

Let L be the line  passing through the point $$P1$$,$$2$$,$$0$$ and perpendicular to the plane r¯⋅$$3i$$¯$$+4k$$¯$$=0$$ if line  intersects the plane r¯⋅i¯−j¯$$+k$$¯$$=13$$ at point Q, then  Q is

Infinity Learn · Accepted Answer

The equation of the line passing through the point  $$P1$$,$$2$$,$$0and$$ perpendicular to the plane r¯⋅$$3i$$¯$$+4k$$¯$$=0$$  is x−$$13=y$$−$$20=z$$−$$04=kThe$$ general point on the above line $$is3k+1$$,$$2$$,$$4kThis$$ point lies on the planex−$$y+z=13It$$ implies that    $$3k+1$$−$$2+4k=137k=14k=2$$         Therefore, the $$pointQ7$$,$$2$$,$$8$$

Let $L$ be the line passing through the point $P (1, 2, 0)$ and perpendicular to the plane $\bar{r} \cdot (3 \bar{i} + 4 \bar{k}) = 0$ if line intersects the plane $\bar{r} \cdot (\bar{i} - \bar{j} + \bar{k}) = 13$ at point $Q$ , then $Q$ is

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Let L be the line passing through the point P1,2,0 and perpendicular to the plane r¯⋅3i¯+4k¯=0 if line intersects the plane r¯⋅i¯−j¯+k¯=13 at point Q, then Q is

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Let $L$ be the line passing through the point $P (1, 2, 0)$ and perpendicular to the plane $\bar{r} \cdot (3 \bar{i} + 4 \bar{k}) = 0$ if line intersects the plane $\bar{r} \cdot (\bar{i} - \bar{j} + \bar{k}) = 13$ at point $Q$ , then $Q$ is