Let L1 and L2 be two lines intersecting at P. IfA1,B1,C1 are points on L1,A2,B2,C2,D2,E2 are points on L2 and if none of these coincides with P, then the number of triangles formed by these 8 points is

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answer is D.

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Detailed Solution

=8c3−3c3−5c3=45 the number of triangles formed by 8 points is15

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