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Let 3π4<θ<π and 2 cotθ+1sin2θ= k−cotθ then k is equal to

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a

1

b

–1

c

0

d

12

answer is B.

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Detailed Solution

G.E=2cotθ+(1+cot2θ) =−(1+cotθ) , (since 3π4<θ<π , cotθ<−1, ⇒ (1+cotθ<0) )=−1−cotθ , k=−1

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