Story
NEET AITS
Story
Mock Tests
Story
Live Class
Story
JEE AITS

Questions  

Let 0<P(A)<1, 0<P(B)<1 and P(AB)=P(A)+P(B)P(A)P(B) then which of the following is correct?

Unlock the full solution & master the concept.

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
By Expert Faculty of Sri Chaitanya
a
PBA=P(B)−P(A)
b
P(A¯∪B¯)=P(A¯)+P(B¯)
c
P(A∪B¯)=P(A¯)P(B¯)
d
PAB=P(A)

Ready to Test Your Skills?

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is C

We know thatP(A∪B)=P(A)+P(B)−P(A∩B)∴ Here, P(A∩B)=P(A)P(B)⇒ A, B are independent events.⇒A, Bc¯; Ac, B  and  Ac¯, Bc¯ also pairwise independent events.∴P(A∪B¯)=P(A¯∩B¯)=P(A¯)P(B¯) and P(A/B)=P(A∩B)P(B)=P(A).
ctaimg

ctaimg

Similar Questions

If A and B are two events such that P(A) = 0.6 and P(B) = 0.8, if the greatest value that P(A/B) can have is p, then the value of 8p is ________.

Want to Improve your productivity
talk to our academic experts now !!

counselling
india
+91

whats app icon