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Let M be a 3 x 3 non-singular matrix with

det(M)=α. If M1adj(adjM)=kI, then the value of k is 

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detailed solution

Correct option is B

We know that M (adj M) = det (M) I⇒    det⁡(M)M−1(adj⁡(adj⁡M))=α2I∵M−1=1|M|adj⁡(M)⇒    αM−1(adj⁡(adj⁡M))=α2I⇒    M−1(adj⁡(adj⁡M))=αI But,     M−1(adj⁡(adj⁡M))=kHence, k=α


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