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Let m and n be two digit natural numbers. The number of pairs (m, n) such that n can be subtracted from m without borrowing is:

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a
2475
b
2550
c
2675
d
2875

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detailed solution

Correct option is A

Suppose m=10a+b and n=10c+d where 1≤a,c≤9 and 0≤b,d≤9.Note that 0≤d≤b Thus d can take (b+1) values. Similarly, 1≤c≤a, therefor, c can take a values. Hence, the required number of pairs (m,n) is (1+2+…+10)(1+2+…+9)=2475


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