Q.
Let a1,a2,a3,…,an be in G.P. such that 3a1+7a2+3a3−4a5=0. Then common ratio of G.P. can be
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a
2
b
32
c
52
d
-12
answer is B.
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Detailed Solution
Given3a1+7a2+3a3−4a5=0⇒7a1+a2+a3=4a1+a3+a5⇒71+r+r2=41+r2+r4⇒7=4r2−r+1⇒4r2−4r+1=4⇒(2r−1)2=4⇒2r−1=±2⇒r=3/2,−1/2
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