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Let an be the nth term of an A.P. If r=1100a2r=α and r=1100a2r1=β, then the common difference of the A.P. is:

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a
α-β
b
1100α-β
c
β-α
d
1200α-β

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detailed solution

Correct option is B

Let d the common difference of the A.P., then     α−β=∑r=1100 a2r−a2r−1=∑r=1100 d=100d⇒    d=1100(α−β)


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