Let N be the set of non-negative integers, I the set of integers, Np the set of non-positive integers, E the set of even integers and P the set of prime numbers. Then
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a
I−N=Np
b
N∩Np=ϕ
c
E∩P=ϕ
d
NΔNp=I−{0}
answer is D.
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Detailed Solution
N= 0,1,2,3,....... I = ......,-2,-1,0,1,2,...... Np=........-2,-1,0 E =2,4,6,........ P = 2,3,5,........ NΔNp=N−Np∪Np−N={1,2,…}∪{…−2,−1}=I−{0}