Let A and B be two non-zero square matrices. If the productAB is a null matrix, then
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a
A and B are singular
b
B is non-singular
c
A is non-singular
d
None of these
answer is A.
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Detailed Solution
Let B be non-singular, then B−1 exists. Now, AB=O (given)⇒ (AB)B−1=OB−1 (post-multiplying both sides by B−1 )⇒ A(BB−1)=O (by associativity)⇒ AIn=O (∵ BB−1=In) ⇒ A=O But A is non-null matrix. Hence, b is a singular matrix.Similarly, it can be shown that A is a singular matrix.