Let n=2015 The least positive integer k for which kn2n2−12n2−22n3−32…n2−(n−1)2=r! for some positive integer r is
2014
2013
1
2
We can rewrite the given expression as
kn2(n−1)(n+1)(n−2)(n+2)(n−3)(n+3)……….(n+n−1)(n−n+1)=r!
⇒kn(1)(2)…(n−1)n(n+1)(n+2)…(2n−1)=r!⇒kn(2n−1)!=r!
∴ To convert L.H.S. to a factorial, we shall require
k = 2 which will convert it into (2n)!