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Parabola

Question

 Let the normal to parabola y2=4ax at P meets the curve again in Q . If PQ and the  normal at Q makes angles α and β respectively with the positive x -axis in positive  direction, then tanα(tanα+tanβ) is equal to 

Moderate
Solution

 Let P=at12,2at1&Q=at22,2at2

 Equation of the normal at Pt1 is y+xt1=2at1+at13.(1)

 Slope of the normal at Pt1 is t1=tanα

 Similarly Slope of the normal at Qt2 is t2=tanβ

 (1) is passing through Qat22,2at2

2at2+at22t1=2at1+at132at2t1=at1t12t222at1t2=at1t1+t2t1t22=t1t1+t22=tanα(tanαtanβ)tanα(tanα+tanβ)=2



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