Let O be the centre of the circle x2+y2=r2 , where r>52 . Suppose PQ is a chord of this circle and the equation of the line passing through P and Q is 2x+4y=5 . If the centre of the circumcircle of the triangle OPQ lies on the line x+2y=4 , then the value of r is
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answer is 2.
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Detailed Solution
OA=52 OC=45CQ=OC=45 and CA=distance between the given parallel lines=325∴ OQ=OA2+AQ2=OA2+CQ2−CA2⇒ 54+165−920=4⇒ 2=r