Let O(0, 0), P(3, 4), and Q(6,0) be the vertices of triangle OPQ. The point R inside the triangle OPQ is such that the triangles OPR, PQR, OQR are of equal area. The coordinates of R are
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a
(4/3,3)
b
(3,2/3)
c
(3,4/3)
d
(4/3,2/3)
answer is C.
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Detailed Solution
Ar(ΔOPR)=Ar(ΔPQR)=Ar(ΔOQR)R should be the centroid of △PQO whose coordinates are3+6+03,4+0+03≡3,43