Let O(0, 0), P(3, 4), Q(6, 0) be the vertices of the triangle OPQ. The point R inside the triangle OPQ is such that the triangles OPR, PQR, OQR are of equal area. The coordinates of R are

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43,3

3,23

3,43

43,23

answer is C.

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Detailed Solution

Point R is the centroid of the triangle OPQ∴R is 0+3+63,0+4+03≡3,43( ∵In ΔABC, with centroid G, areas of ΔGBC, ΔGCA & ΔGAB are equal)

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